What are the details of the hula-hoop rolling down the hill?

Question

Jermey · Answer

Explanation:

A .4Kg hula-hoop is rolled down a hill with a diameter of 1.2m. The hula-hoop completes 3.4 rotations every 2.8 seconds.

To find the linear velocity of the hoop as it comes down the hill, we first calculate the displacement:

Circumference of the hula-hoop = 2 x π x radius = 2 x π x 0.6 = 3.7699 meters

Displacement = Circumference x number of rotations = 3.7699 x 3.4 = 12.8176 meters

Linear velocity (V) = Displacement / Time taken = 12.8176 / 2.8 = 4.58 m/s

Therefore, the linear velocity of the hula-hoop as it comes down the hill is 4.58 meters per second.