Velocity of Cliff Divers in Acapulco, Mexico
How fast are the cliff divers in Acapulco, Mexico going when they hit the water?
The cliff divers at Acapulco, Mexico, jump off a cliff 26.7 m above the ocean. What is their velocity when they hit the water?
Answer:
The speed at which the cliff divers in Acapulco hit the water can be calculated using the principles of physics. We can use the equation for free fall motion to find the speed. The equation is:
v = sqrt(2gh)
where v is the velocity (speed) of the diver, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the cliff (26.7 m in this case).
Plugging in the values, we have:
v = sqrt(2 * 9.8 * 26.7)
v = sqrt(525.6)
v ≈ 22.94 m/s
So, when the divers hit the water, they are going approximately 22.94 m/s. This is the main answer to the question.
The cliff divers in Acapulco, Mexico, hit the water at a speed of approximately 22.94 m/s. This calculation is based on the principles of physics and the equation for free fall motion. It is important to note that this calculation ignores air resistance, which would slightly decrease the speed of the divers.
Nonetheless, this speed gives us an idea of how fast the divers are moving when they hit the water, showcasing the excitement and skill involved in this thrilling sport.