Two Fixed Particles on an X-Axis: Reflecting on Electric Fields

How can we calculate the magnitude of the net electric field midway between two fixed particles?

Given information:
- Particle 1 of charge $-4.28 \\times 10^{-7} \\mathrm{C}$ is at the origin
- Particle 2 of charge $+4.28 \\times 10^{-7} \\mathrm{C}$ is at $x_2=22.1$ cm

Calculation of Net Electric Field Magnitude

The magnitude of the net electric field midway between the particles is 0 N/C. The electric fields are in the opposite direction, resulting in the net electric field magnitude formula: |E_{net}| = |E_1 - E_2|

To calculate the net electric field's magnitude, we need to determine the electric fields produced by each charged particle at the midpoint between them.

The electric field produced by particle 1 at the midpoint is calculated using the formula:
$E_1 = k\\frac{q_1}{(0.1105)^2} = 150$ N/C

Similarly, the electric field produced by particle 2 at the midpoint is calculated as:
$E_2 = k\\frac{q_2}{(0.1105)^2} = 150$ N/C

Since the electric fields are in opposite directions, the net electric field magnitude simplifies to: |E_{net}| = |E_1 - E_2| = |150 - 150| = 0 N/C