# Reflecting on the Physics of Falling Objects

## What is the position of a ball released from the top of a tower after T/3 seconds?

a. h/9 metres from the ground

b. 7h/9 metres from the ground

c. 8h/9 metres from the ground

d. 17/18 metres from the ground

## Answer

The position of the ball when it's been falling for T/3 seconds is 8h/9 metres from the ground.

As we contemplate the scenario of a ball being released from the top of a tower and its position after a certain time, we are diving into the realm of physics and the laws that govern the motion of objects under gravity.

The solution to this problem lies in the equation of motion and the fundamental principles of gravitational acceleration and initial velocity. By applying these concepts, we can determine the exact position of the ball in T/3 seconds.

The answer derived from the calculations is c. 8h/9 metres from the ground. This result is obtained by considering the distance covered by the ball in T/3 seconds based on the given parameters.

To arrive at this conclusion, we utilize the equation of motion: s = ut + 0.5gt², where s represents distance, u is initial velocity (which is zero in this case), g is the acceleration due to gravity, and t is time. By substituting the appropriate values and solving for the position at T/3 seconds, we find that the ball is located at 8h/9 metres from the ground.

This calculation exemplifies the application of physics principles in real-world scenarios and highlights the significance of understanding the dynamics of falling objects. By unraveling the mechanics behind the motion, we gain insights into the behavior of objects under the force of gravity.