Optimistic Exploration of Simple Harmonic Motion in the Lab

What is the glider's maximum velocity in Simple Harmonic Motion?

A. 2.333 x 10^-1 m/s

What is the new period of oscillation of the glider/poutine?

A. 3.24 s

What is the new amplitude of motion of the glider/poutine?

A. 0.0546 m

Answer:

The glider's maximum velocity is approximately 0.2333 m/s. The new period of oscillation of the glider/poutine is approximately 3.24 s. The new amplitude of motion of the glider/poutine is approximately 0.0546 m.

In Simple Harmonic Motion, the maximum velocity of an object can be calculated using the formula: vmax = Aω, where A is the amplitude of motion and ω is the angular frequency.

The angular frequency can be calculated using the formula: ω = √(k/m), where k is the spring constant and m is the mass of the object.

Given that the effective spring constant of the system is 1.8 N/m and the mass of the glider is 400 grams (0.4 kg), we can calculate the angular frequency:

ω = √(1.8 N/m / 0.4 kg) = √4.5 rad/s ≈ 2.121 rad/s

Now, we can calculate the maximum velocity:

vmax = Aω = 0.11 m * 2.121 rad/s ≈ 0.2333 m/s

When the blob of poutine with a mass of 80 grams (0.08 kg) is added to the glider, the mass of the system changes to 0.48 kg (0.4 kg + 0.08 kg).

The new period of oscillation can be calculated using the formula: T = 2π/ω. Substituting the new value of ω:

T = 2π/2.121 rad/s ≈ 3.24 s

The new amplitude of motion can be calculated using the formula: A' = A * (m / (m + m_poutine)), where m is the mass of the glider and m_poutine is the mass of the poutine blob. Substituting the values:

A' = 0.11 m * (0.4 kg / (0.4 kg + 0.08 kg)) ≈ 0.0546 m

Now you have learned about how to calculate the glider's maximum velocity, new period of oscillation, and new amplitude of motion in simple harmonic motion. Stay optimistic and keep exploring the fascinating world of physics!