Light bulb resistance calculation

What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0.5 A in the bulb?

Given:

Potential difference (V) = 120 V

Current (I) = 0.5 A

Find the resistance of the light bulb.

Answer:

The resistance of a light bulb is 240 ohms.

Explanation:

To calculate the resistance of a light bulb, we can use Ohm's law which states that V = IR, where V is the potential difference, I is the current, and R is the resistance.

Given that the potential difference is 120 V and the current is 0.5 A, we can plug these values into the formula:

R = V / I

R = 120 V / 0.5 A

R = 240 ohms

Therefore, the resistance of the light bulb is 240 ohms. This is the required solution.