Force Required to Keep the Top Plate Moving at 18 m/s

What is the force required to keep the top plate moving at 18 m/s if it has an area of 2 m2?

Given the viscosity of water is 0.89 centipoise and the distance between the plates is 1 cm.

Answer:

The force required to keep the top plate moving at a velocity of 18 m/s is 3.204 N.

To calculate the force required to keep the top plate moving at a constant velocity, we use the equation:

F = (nAv) / L

Where:

F is the force,

n is the coefficient of viscosity (0.89 centipoise),

A is the area of the plate (2 m2),

v is the velocity (18 m/s), and

L is the distance between the plates (1 cm).

Substitute the given values into the equation:

F = (0.89 centipoise * 2 m2 * 18 m/s) / 1 cm

Converting units and simplifying:

F = (0.89 * 10^(-2) Ns/m2 * 2 m2 * 18 m/s) / (1 * 10^(-2) m)

Therefore, the force required to keep the top plate moving at a velocity of 18 m/s is 3.204 N.

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