Energy Output Calculation in Machine Efficiency

How is the energy output of a machine calculated based on its efficiency?

An electric motor with a 1200 hp output drives a machine with an efficiency of 60%. What is the energy output of the machine per second?

Answer:

536,904 J/s

Calculating the energy output of a machine based on its efficiency involves understanding how efficiency and energy input relate to energy output. In the given data, the electric motor has a 1200 hp output, and it drives a machine with an efficiency of 60%.

The formula for efficiency is expressed as [tex]n=\\frac {E_o}{E_i}[/tex], where n represents efficiency, E represents energy, and subscripts o and i represent output and input respectively.

Since the input energy in the machine is known (1200 hp), we can calculate the energy output by multiplying the input energy by the efficiency. In this case, the energy output is 0.6 * 1200 hp = 720 hp.

To convert horsepower (hp) to joules per second (J/s), we multiply by the conversion factor 745.7. Therefore, the energy output in joules per second is 720 * 745.7 = 536,904 J/s.