# Calculating the Distance Traveled by a Car

## Question:

A car moving with an initial speed of 16 meters per second is brought to rest uniformly in 4.0 seconds. How far does the car travel during this 4.0-second interval?

## Answer:

The car travels 64 meters.

**Calculating the Distance Traveled by a Car**

When the car is brought to rest uniformly, it means that its initial speed decreases to zero at a constant rate. To find the distance traveled by the car during this interval, we can use the formula:

**d = v _{0}t + 0.5at^{2}**

where:

**d** = distance traveled

**v _{0}** = initial speed = 16 m/s

**t** = time interval = 4.0 seconds

**a** = acceleration (negative value as the car is decelerating)

Given that the initial speed of the car is 16 m/s and it comes to rest in 4.0 seconds, we can calculate the acceleration using the formula:

**a = (v - v _{0}) / t**

**a = (0 - 16) / 4.0 = -4 m/s ^{2}**

Substitute the values of **v _{0}**,

**t**, and

**a**into the distance formula:

**d = 16(4.0) + 0.5(-4)(4.0) ^{2}**

**d = 64 meters**

Therefore, the car travels a distance of **64 meters** during the 4.0-second interval while being brought to rest uniformly.