Calculating the Capacitance of a Parallel-Plate Capacitor
What is the capacitance of the capacitor?
Find the capacitance of a parallel-plate capacitor with the given data:
- Dielectric constant (K): 2.1
- Area of plates (a): 0.063 m × 5.4 m
- Distance between the plates (d): 3.5 × 10⁻⁵ m
Answer: 0.18
The capacitance of the capacitor is 0.18 μF.
To calculate the capacitance (C) of a parallel-plate capacitor, you can use the formula:
C = (K * ε * a) / d
Where:
- K = Dielectric constant = 2.1
- ε = Permitivity of free space = 8.85 x 10⁻¹² C²/Nm²
- a = Area of plates = 0.063 m × 5.4 m = 0.302 m²
- d = Distance between the plates = 3.5 × 10⁻⁵ m
Plugging in the values:
C = (2.1 * 8.85 x 10⁻¹² * 0.302) / (3.5 x 10⁻⁵)
C = 1.8 x 10⁻⁷ F = 0.18 μF
Therefore, the capacitance of the capacitor is 0.18 μF.