# Calculate Sound Level if Only One Firecracker Explodes

## Calculating Sound Level with Only One Firecracker Exploding

When two firecrackers are exploded simultaneously at a certain place, the sound level produced is 86 decibels (db). Now, we need to calculate what the sound level will be if only one firecracker is exploded.

## Formula for Sound Intensity in Decibels

By definition, the sound intensity, I, in terms of decibels is given by the formula:

**I _{db} = 10 log(^{I}/_{I0})**

where I_{0} is the reference intensity.

## Calculations

When two sound sources are present, the equation becomes:

**10 log( ^{2I}/_{I0}) = 86**

By solving the equation, we get:

**I/I _{0} = 2715.83**

## Sound Level with One Firecracker

Therefore, with only one sound source, the decibel level is:

**10 log(2715.83) = 34.3 db**

If two firecrackers produce a sound level of 86 db when fired simultaneously at a certain place, what will be the sound level if only one is exploded?

By adding the intensities of the sound sources and then applying the formula for sound intensity in decibels, the sound level with only one firecracker exploding will be 34.3 decibels.