# Emergency Preparedness Kits Distribution Calculation

## How many kits can Javier make with the supplies he has?

Javier is making emergency-preparedness kits to share with friends. He has 6 bottles of water and 8 cans of food, which he would like to distribute equally among the kits, with nothing left over. What is the greatest number of kits Javier can make?

## The greatest number of kits Javier can make is 2.

To determine the greatest number of emergency preparedness kits Javier can make with the given supplies, we need to find the greatest common divisor (GCD) of 6 and 8.

In this scenario, Javier wants to share his supplies equally among the emergency-preparedness kits he is making. To ensure that each kit has an equal distribution of resources with no leftovers, we need to find the maximum number of kits he can create.

To find the greatest number of kits, we calculate the greatest common divisor (GCD) of the number of bottles of water (6) and cans of food (8) Javier has at his disposal. The GCD represents the maximum number of kits that can be evenly distributed without any resources remaining unused.

Here is the step-by-step process to determine the greatest number of kits Javier can make:

**Step 1:** Find the prime factors of 6 and 8.
- The prime factorization of 6 is 2 * 3.
- The prime factorization of 8 is 2 * 2 * 2.

**Step 2:** Determine the common factors.
- The common factor between 6 and 8 is 2.

**Step 3:** Calculate the GCD.
- The GCD of 6 and 8 is 2.

The GCD of 6 and 8 is 2, indicating that Javier can make a maximum of 2 kits with the given supplies. Each kit would contain 3 bottles of water and 4 cans of food, ensuring an equal distribution among the kits.

Therefore, the greatest number of kits Javier can make is 2, providing assistance to his friends in times of emergency.