Calculating Number of Loops for Time Delay Using Micro-controller
How many loops do we need for a 130 ms time delay using a Micro-controller with 20-MHZ bus clock and 150 E-cycles in total?
N = (T * F) / E
N is the number of loops
T is the desired time delay in milliseconds
F is the clock frequency in megahertz
E is the number of E-cycles per loop
In this case, we have:T = 130 ms
F = 20 MHz
E = 150
Plugging these values into the formula, we get:N = (130 ms * 20 MHz) / 150 = 193 loops
Therefore, we need to execute 193 loops to create a 130 ms time delay.Detailed Calculation Process:
1. Convert the desired time delay from milliseconds to seconds:130 ms / 1000 = 0.13 s
2. Multiply the time delay in seconds by the clock frequency in megahertz:0.13 s * 20 MHz = 2.6 MHz
3. Divide the number of clock cycles by the number of E-cycles per loop to get the number of loops:2.6 MHz / 150 = 193 loops
Therefore, we need to execute 193 loops to create a 130 ms time delay.