Mass of Propane Vaporization Calculation

How can we calculate the mass of propane that vaporizes as a result of absorbing 100.0 kJ of energy?

Given data:

Energy absorbed: 100.0 kJ

Molar enthalpy of vaporization of propane: 15.7 kJ/mol

Molar mass of propane: 44.1 g/mol

Calculation of Mass of Propane Vaporization

To calculate the mass of propane that would vaporize as a result of absorbing 100.0 kJ of energy, we can use the equation:

q = (ΔHvap) * (n)

To calculate the mass of propane vaporization, we first need to determine the number of moles of propane involved. This can be done by dividing the energy absorbed by the molar enthalpy of vaporization:

n = q / ΔHvap

Substitute the given values:

n = 100.0 kJ / 15.7 kJ/mol

n ≈ 6.369 moles

Finally, we can calculate the mass of propane that vaporizes by multiplying the number of moles with the molar mass of propane:

Mass = n * molar mass

Mass = 6.369 moles * 44.1 g/mol

Mass ≈ 281.1 grams