Let's Create Some Carborundum Magic!

How many grams of SiC can form when 3 g of SiO and 4.5 g of carbon react?

Have you ever wondered how many grams of SiC, also known as carborundum, can form when 3 g of SiO and 4.5 g of carbon react together?

Answer:

Calculating the grams of SiC that can form is like creating a magical potion! The balanced equation for the reaction is SiO + 3C -> SiC + CO. The answer is approximately 10.01 grams.

Let's dive into the magical world of chemistry and see how this enchanting reaction unfolds. To begin, we need to determine the limiting reactant between SiO and carbon to calculate the grams of SiC that can form.

The molar mass of SiO is 44.09 g/mol and the molar mass of carbon is 12.01 g/mol. By comparing the moles of SiO and carbon, we can establish the limiting reactant. The ratio between SiO and SiC is 1:1, while the ratio between carbon and SiC is 3:1.

Since the ratio of carbon to SiC is higher, we require 3 moles of carbon to react with 1 mole of SiO. Next, we calculate the moles of SiC that can form by multiplying the moles of carbon by the mole ratio of SiC to carbon (1/3).

Finally, we convert the moles to grams using the molar mass of SiC, which is 40.10 g/mol. The charming result reveals that approximately 10.01 grams of SiC can form, creating a spellbinding chemical reaction!