Kinetic Energy Calculation of a Person in an Elevator

What is the kinetic energy of a person with a mass of 82 kg in an elevator moving at a speed of 5m/s?

Calculate the kinetic energy of the person based on the given data.

The person’s kinetic energy is 1,025 J

The kinetic energy of a person weighing 82 kg in an elevator moving at a speed of 5m/s is 1,025 Joules (J).

Kinetic energy is a form of energy associated with bodies that are in motion. It depends on the mass and speed of the moving body. The formula to calculate kinetic energy is K.E = ½ mv², where K.E is the kinetic energy in Joules (J), m is the mass in kilograms (kg), and v is the velocity in meters per second (m/s).

In this case, the mass of the person is 82 kg and the speed of the elevator is 5m/s. Plugging these values into the formula, we get:

K.E = ½ × 82 kg × (5 m/s)²

K.E = ½ × 82 kg × 25 m²/s²

K.E = 41 kg m²/s² = 41 Joules (J)

Therefore, the kinetic energy of the person with a mass of 82 kg in an elevator moving at a speed of 5m/s is 1,025 J.