Ideal Gas Law Calculation

What is the temperature in Kelvin of a gas with 2.20 moles, 3.30L volume, and 3.50 atm pressure?

Answer:

The temperature of the gas is approximately 146.5 Kelvin.

The question asks us to calculate the temperature in Kelvin of a gas using the ideal gas law. The ideal gas law equation is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature.

In this case, we are given the values of P = 3.50 atm, V = 3.30 L, and n = 2.20 moles. By substituting these values into the ideal gas law equation and solving for T, we find that the temperature of the gas is approximately 146.5 Kelvin.

It is important to remember that the ideal gas constant, R, is 0.0821 atm·L/mol·K when using pressure in atm and volume in liters. This constant helps us calculate the temperature in Kelvin accurately.