How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?
Calculation of moles of oxygen produced
2KClO₃ = 2KCl + 3O₂
Given:
n(KClO₃) = 2 mol
n(O₂) = 3/2 * n(KClO₃)
n(O₂) = 1.5 * 2 mol = 3 mol
Therefore, 3 moles of oxygen are produced.
How many moles of oxygen are produced when 2 mol of potassium chlorate decompose?The moles of oxygen gas produced will be 3 moles. Explanation: For the given chemical reaction: 2KClO₃ -> 2KCl + 3O₂ By Stoichiometry of the reaction: If 2 moles of potassium chlorate produces 3 moles of oxygen gas. So, 2 moles of potassium chlorate will produce = 3/2 * 3 = 3 moles of oxygen gas. Hence, the moles of oxygen gas produced will be 3 moles.