How Many Molecules in 923 Grams of CaF2?

Calculation of Molecules in 923 Grams of CaF2

When you have a sample of 923 grams of CaF2, you may wonder how many molecules are present in that amount. To find out the answer, we need to go through some calculations.

Step 1: Calculate the number of moles of CaF2

First, we need to determine the molar mass of CaF2, which is 78.08 g/mol. By using dimensional analysis, we can set up the following calculation:

923 g CaF2 x (1 mol CaF2 / 78.08 g CaF2) = 11.82 moles of CaF2

Step 2: Find the total number of molecules

Now that we know we have 11.82 moles of CaF2, we can use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to find the total number of molecules:

11.82 moles of CaF2 x (6.022 x 10^23 molecules/mol) = 7.12 x 10^24 molecules of CaF2

Final answer:

The number of molecules in 923 grams of CaF2 is 7.12 x 10^24 molecules.

Explanation:

By following the calculations above, we have determined that there are 7.12 x 10^24 molecules present in 923 grams of CaF2. This result is based on the molar mass of CaF2 and Avogadro's number, which allowed us to convert grams to moles and then to molecules.

What is the final number of molecules in 923 grams of CaF2? The final number of molecules in 923 grams of CaF2 is 7.12 x 10^24 molecules.
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