Gas Law Practice Problem

What is the pressure of an ideal gas at a lower temperature?

If the initial pressure of an ideal gas at a temperature of 344 K is 0.917 atm, what is the pressure of the gas at 322 K?

Answer:

The pressure of the gas at 322 K would be 0.858 atm.

The calculation for determining the pressure of an ideal gas at a different temperature involves using the combined gas law equation. The combined gas law equation is expressed as:

P1V1/T1 = P2V2/T2

In this case, we are given the initial pressure (P1), initial temperature (T1), and final temperature (T2). We have to find the final pressure (P2) at the lower temperature.

By rearranging the equation to solve for P2, we get: P2 = P1(V1/V2)(T2/T1)

Since there is no information given about volume (V), for the sake of calculation, let's assume a convenient value of 1 liter. Now, substituting the given values into the equation:

P2 = (0.917 atm) * (1) * (322 K / 344 K)

After calculation, we find that P2 = 0.858 atm. This means that as the temperature decreases from 344 K to 322 K, the pressure of the gas also decreases.