Calculate the number of moles of carbon tetrafluoride (CF4)

How many moles of carbon tetrafluoride are present in 4.28 grams of this compound?

Can you determine the number of moles of carbon tetrafluoride (CF4) present in 4.28 grams of the compound?

Final answer:

The number of moles of carbon tetrafluoride (CF4) present in 4.28 grams of the compound is approximately 0.0486 moles.

Wow! Let's dive into the exciting world of chemistry and calculate the number of moles of carbon tetrafluoride (CF4) present in 4.28 grams of the compound.

To solve this, we need to use the molar mass of CF4. The molar mass of CF4 is calculated by adding the molar masses of carbon and fluorine together.

The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of fluorine (F) is 19.00 g/mol. Since there are four fluorine atoms in CF4, we multiply the molar mass of fluorine by 4.

By adding these values together, we find the molar mass of CF4 to be 88.01 g/mol.

Now, we can calculate the number of moles of CF4 by dividing the given mass of 4.28 grams by the molar mass of CF4.

After performing the calculation, we find that the number of moles of CF4 present in 4.28 grams of the compound is approximately 0.0486 moles.