A Bike Rider's Kinetic Energy and Hill Height Calculation
A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike and the rider is 85 kg.
Find the kinetic energy of the bike and the rider.
KE=3070.625 J
Further explanation
mass of bike+rider = 85 kg
velocity = 8.5 m/s
KE = 1/2 * m * v^2
KE = 1/2 * 85 * 8.5^2
KE = 3070.625 J
Conservation of energy:
(KE+PE)₁ (downhill) = (KE+PE)₂ (up the hill)
PE₁ = 0 ⇒ h = 0
KE₂ = 0 ⇒ v = 0 (stop), so the equation becomes:
KE₁ = PE₂
KE₁ = 3070.625
KE₁ = mgh₂
3070.625 = 85 * 9.8 * h ⇒ h = 3.686 m
If the rider coasts up the hill, calculate the height at which the bike will come to a stop.
Height = 3.686 m
Please help me!! this is due in like 20 minutes!! To calculate the kinetic energy of the bike and the rider, use the formula KE = 1/2 * m * v^2 where m is the mass and v is the velocity. In this case, the kinetic energy is 3070.625 J. For determining the height at which the bike will come to a stop when coasting up the hill, consider the conservation of energy principle. The potential energy at the starting point is zero and the kinetic energy at the ending point (when the bike comes to a stop) is zero. By equating the initial kinetic energy to the final potential energy, you can solve for the height, which in this case is 3.686 meters.