A 10.0 mL Syringe: Calculating Pressure Inside

Calculating Pressure Inside a 10.0 mL Syringe

A 10.0 mL syringe contains 0.10 g of nitrogen gas at 0.0 degrees Celsius. What is the pressure inside the syringe?

Since the sample inside the syringe is a gas, we assume that it is an ideal gas, which means we can use the ideal gas law equation PV = nRT. Let's calculate the pressure inside the syringe:

n = m / M

Where:

n = number of moles

m = mass of the gas (0.10 g)

M = molar mass of nitrogen gas (28 g/mol)

Plugging in the values, we get:

n = 0.10 / 28 = 0.0036 mol

P = nRT / V

Where:

P = pressure

R = ideal gas constant (0.08206 atm·L/mol·K)

T = temperature in Kelvin (0 degrees Celsius = 273.15 K)

V = volume of the syringe (10.0 mL = 0.010 L)

Substitute the values into the equation:

P = 0.0036(0.08206)(273.15) / 0.010

P = 8 atm

What is the pressure inside the 10.0 mL syringe that contains 0.10 g of nitrogen gas at 0.0 degrees Celsius?

The pressure inside the syringe is 8.0 atm.