# Calculate the Mass Percent of Sulfuric Acid in Water Solution

What is the mass percent of sulfuric acid (H2SO4) in a solution containing 583 g of H2SO4 in 1.50 kg of water?

## Calculation of Mass Percent

**The question is about calculating the mass percent of sulfuric acid (H2SO4) in water, which is a common concentration measure in chemistry.**

The given scenario involves a solution with 583 g of H2SO4 in 1.50 kg of water. To determine the mass percent of H2SO4 in the solution, we need to consider the total mass of the solution. In this case, the total mass is the sum of the mass of H2SO4 and the mass of water.

Firstly, we convert the mass of water from kilograms to grams. 1.50 kg is equivalent to 1500 g. Therefore, the total mass of the solution is 583 g (H2SO4) + 1500 g (water), which equals 2083 g.

To calculate the mass percent of H2SO4 in the solution, we use the formula:

Mass Percent = (Mass of Solute / Total Mass of Solution) * 100%

Substituting the values into the formula, we get:

Mass Percent = (583 g / 2083 g) * 100% = 28%

Therefore, the solution's mass percent of H2SO4 is approximately 28%. This indicates that the solution contains 28% sulfuric acid by mass.

**Explanation:**

The student's query pertains to a solution of sulfuric acid (H2SO4) in water, which involves the concept of mass percent commonly used in chemistry to express the concentration of a solution.

In this context, the mass of H2SO4 is 583 g and the mass of water is 1500 g. By calculating the mass percent, we determine the proportion of H2SO4 in the total mass of the solution.

Through the calculation process, we find that the solution with 583 g of H2SO4 in 1.50 kg of water has a mass percent of approximately 28% H2SO4. This signifies that the solution consists of 28% sulfuric acid by mass.